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后端Lua

if string.find(szbl, CharacterFashionMap[str][1]..":0") then 这一行我需要看哪个值为nil 怎么去输出他

后端Lua

这样能输出出来吗

后端Lua

这个可以直接print么

后端Lua

是什么原因呢

后端Lua

local npc = {} function npc.main(actor, param1, param2, param3, str) sendluamsg(actor, 10713, 105, 1, 0, getplaydef(actor, "T88")) end local CharacterFashionMap = { ["[N]沈沧海-A"] = {"时装1_1","时装1_","[N]沈沧海"}, ["[N]沈沧海-B"] = {"时装1_2","时装1_"

后端Lua

function ds_fwqjs(actor, param1, param2, param3, str) if param2 == 1 then npcliby[param1].main(actor, param1,param2,param3,str) elseif param2 == 2 then npcliby[param1].link(actor, param1, param2, param3, str) elseif param2

后端Lua

npcliby

后端Lua

(szbl, CharacterFashionMap[str][1]..":0")

后端Lua

CharacterFashionMap

后端Lua

if string.fin

后端Lua

if string.find(szbl, CharacterFashionMap[str][1]..":0") then

后端Lua

local szbl = getplaydef(actor, "T88")

后端Lua

这段里面 szbl值为空 怎么处理

后端Lua

szbl这个函数为空会报错么日

后端Lua

local npc = {} function npc.main(actor, param1, param2, param3, str) sendluamsg(actor, 10713, 105, 1, 0, getplaydef(actor, "T88")) end local CharacterFashionMap = { ["[N]沈沧海-A"] = {"时装1_1","时装1_","[N]沈沧海"}, ["[N]沈沧海-B"] = {"时装1_2","时装1_"