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前端Lua

[LUA-print] stack traceback: [string "scripts/GUI/GUI.lua"]:101: in function 'CheckIsInvalidCObject' [string "scripts/GUI/GUI.lua"]:2414: in function 'Text_setTextColor' [string "GUILayout/PlayerFrame_win32.lua"]:221: in funct

前端Lua

LUA ERROR: [string "GUILayout/skill/FeiJianSkill.lua"]:669: attempt to call method 'registerluaNetMsg' (a nil value)

前端Lua

LUA ERROR: [string "GUILayout/skill/FeiJianSkill.lua"]:669: attempt to index global 'sl' (a nil value)

前端Lua

-- 将堆转换为栈 提升速度 local GUI=GUI GUINpc=function (uiname) local w,h=SL:GetMetaValue("SCREEN_WIDTH"),SL:GetMetaValue("SCREEN_HEIGHT") local root =GUI:Win_Create("win",w/2,h/2) GUI:LoadExport(root, "NewUI/"..uiname) -- delegate 从父组件里面

前端Lua

[LUA-print] [13:41:55-905] nativeUI => userdata: 0x293a94e8 [LUA-print] [13:41:55-905] bg => userdata: 0x293cf108

前端Lua

local ui=GUI:ui_delegate(root) 怎么拿到ui里面的每一个值

前端Lua

帮我打上注释

前端Lua

local npc = {} function npc.main(actor, param1, param2, param3, str) sendluamsg(actor, 10713, 105, 1, 0, getplaydef(actor, "T88")) end local CharacterFashionMap = { ["[N]沈沧海-A"] = {"时装1_1","时装1_","[N]沈沧海"}, ["[N]沈沧海-B"] = {"时装1_2","时装1_"

前端Lua

local longwenbaoshi = {} function longwenbaoshi.main(param1, param2, param3, param4) lib:Require(param1, function(state) if state then if param1 then longwenbaoshi.parent = lib:openwin(param1, nil, true, param

前端Lua

if GUI:Win_IsNotNull(ui["shengm"]) then local shengm_value = cfg[var+1].cur_attr_8 or 0 GUI:Text_setString(ui["shengm"], tostring(shengm_value) .. "%")-为什么我的ui["shengm"]是个nil

前端Lua

[string "scripts/util/util.lua"]:962: attempt to call field 'setString' (a nil value) local longwenbaoshi = {} function longwenbaoshi.main(param1, param2, param3, param4) lib:Require(param1, function(state) if state then if p

前端Lua

SL:RegisterLuaNetMsg(1506, FeiJianSKill.onFeiJianHit, FeiJianSKill)

前端Lua

[string "GUILayout/NPC/zhuansheng.lua"]:272: attempt to compare string with number function zhuansheng.upmain() SL:print("===== 更新转生界面 =====") if not zhuansheng.parent or not zhuansheng.parent._ui then SL:print("❌ 错误: parent

前端Lua

怎么删除 父节点下组件

前端Lua

table.unpack (list [, i [, j]]) 返回列表中的元素。 这个函数等价于 return list[i], list[i+1], ···, list[j] i 默认为 1 ,j 默认为 #list。 这是解包命令吗