前端Lua
前端Lua
前端Lua
怎么删除 父节点下组件
前端Lua
table.unpack (list [, i [, j]]) 返回列表中的元素。 这个函数等价于 return list[i], list[i+1], ···, list[j] i 默认为 1 ,j 默认为 #list。 这是解包命令吗
前端Lua
SL:toServer(unpack(cfg.cmd))
前端Lua
SL:toServer
前端Lua
GUI:delChildByName
前端Lua
delChildByName
前端Lua
现在问题是没有加速的过程,整个过程的速度都是一样的
前端Lua
SL:print("打开抽奖界面") local lottery = {} local itemPos = { {46, 340}, {139, 340},{232, 340}, {325, 340}, {418, 340}, {490, 340}, {573, 340}, {697, 340}, {46,256},{697,256}, {46,172},{697,172}, {46, 88}, {139, 88},{232, 88}, {325, 88},
前端Lua
[LUA-print] ---------------------------------------- [LUA-print] LUA ERROR: [string "scripts/GUI/GUI.lua"]:1934: attempt to call method 'getChildByName' (a nil value) [LUA-print] stack traceback: [string "scripts/main.lua"]:14: in function '
前端Lua
SL:print("打开抽奖界面") local lottery = {} local itemPos = { {46, 340}, {139, 340},{232, 340}, {325, 340}, {418, 340}, {490, 340}, {573, 340}, {697, 340}, {46,256},{697,256}, {46,172},{697,172}, {46, 88}, {139, 88},{232, 88}, {325, 88},
前端Lua
SL:print("打开抽奖界面") local lottery = {} local itemPos = { {46, 340}, {139, 340},{232, 340}, {325, 340}, {418, 340}, {490, 340}, {573, 340}, {697, 340}, {46,256},{697,256}, {46,172},{697,172}, {46, 88}, {139, 88},{232, 88}, {325, 88},
前端Lua
重新封装 模块名字是menu 变量名字不要那么长 并且我传入一级菜单 二级菜单的tabl 你来创建就可以 大小就默认 他们的x , y 都在一列
前端Lua
local mainWindow = GUI:Win_Create("MenuWindow", 0, 0, 0, 0, false, false, true, false, false, false, 1) -- 一级菜单配置(调整位置,留出二级菜单空间) local primaryMenus = { {x = 50, y = 400, width = 100, height = 40, text = "菜单1"}, {x = 50, y = 350, width = 100,
前端Lua