Lua十进制转二进制：除2取余的倒排构建

local function toBin(n)
    local s = ""
    while n > 0 do
        s = s .. (n % 2)            -- 低位在前，顺序反了
        n = math.floor(n / 2)
    end
    return s
end

local function toBin(n)
    local t = {}
    while n > 0 do
        table.insert(t, 1, n % 2)   -- 新余数压到最前，倒排
        n = math.floor(n / 2)
    end
    return table.concat(t)
end
sendmsg(actor, 1, "怪物血量10的二进制 " .. toBin(10))