【框架设计】时装染色：染色剂配方与色值校验的框架设计

local RECIPES = {
    ["300"] = "绯红", ["030"] = "柠黄", ["003"] = "靛蓝",
    ["210"] = "橙金", ["201"] = "紫棠", ["120"] = "杏黄",
    ["021"] = "翠绿", ["102"] = "绛紫", ["012"] = "湖蓝",
    ["111"] = "玄墨",
}
local function mixKey(r, y, b)
    if r + y + b ~= 3 then return nil end
    return tostring(r) .. tostring(y) .. tostring(b)
end

local BANNED = { "玄墨", "靛蓝" }
function dye(actor, r, y, b)
    local key = mixKey(r, y, b)
    local color = key and RECIPES[key] or nil
    if color == nil then
        sendmsg(actor, 0, "染色剂总量必须是 3 瓶，且配比有效")
        return
    end
    for _, c in ipairs(BANNED) do
        if c == color then
            sendmsg(actor, 0, color .. "为标识禁用色，无法染色")
            return
        end
    end
    if not checkitemw(actor, "染色剂", 3) then
        sendmsg(actor, 0, "染色剂不足 3 瓶")
        return
    end
    takeitem(actor, "染色剂", 3)
    takeitem(actor, "金币", 50000)
    setplayvar(actor, "HUMAN", "FASHION_COLOR", color, 1)
    sendmsg(actor, 0, "染色成功，时装变为" .. color .. "色")
end