【入门夯实】Lua区间判交：沙巴克双活动的时间冲突检测

local function overlap(s1, s2)
    return s1[1] <= s2[2]           -- 只查一端，漏判半重叠
end

local function overlap(s1, s2)
    return s1[1] <= s2[2] and s2[1] <= s1[2]
end
local A = {20 * 3600, 22 * 3600}
local B = {21 * 3600, 23 * 3600}
if overlap(A, B) then
    sendmsg(actor, 1, "沙巴克活动时段冲突，拒绝排期")
end