Lua递增三元组：双哨兵贪心判定

local function hasTriple(t)
    for i = 1, #t do
        for j = i + 1, #t do
            for k = j + 1, #t do    -- 三重循环立方级
                if t[i] < t[j] and t[j] < t[k] then
                    return true
                end
            end
        end
    end
    return false
end

local function hasTriple(t)
    local one, two = math.huge, math.huge
    for _, v in ipairs(t) do
        if v <= one then
            one = v                 -- 更新最小哨兵
        elseif v <= two then
            two = v                 -- 更新次小哨兵
        else
            return true             -- 比两大，三元组成立
        end
    end
    return false
end
sendmsg(actor, 1, "递增三元组："
    .. tostring(hasTriple({5, 1, 6, 2, 7})))