【网络通信】分包策略：大消息的有序分包与重组

-- 大消息分包：切片下发
local player = class(actor)
local CHUNK = 1400
local function sendChunks(player, msgId, payload)
    local total = math.ceil(#payload / CHUNK)
    for i = 1, total do
        local piece = string.sub(payload, (i - 1) * CHUNK + 1, i * CHUNK)
        sendluamsg(player, msgId, i, total, 0, piece)
        setontimer(player, 0, 0, 20, 0)
    end
end

-- 客户端重组：缓存与补拉
local player = class(actor)
local cacheBuf = {}
local function onChunk(player2, msgId, w1, w2, w3, sMsg)
    cacheBuf[#cacheBuf + 1] = {idx = w1, total = w2, data = sMsg}
    if #cacheBuf < w2 then return end
    table.sort(cacheBuf, function(a, b) return a.idx < b.idx end)
    local parts, missing = {}, 0
    for i = 1, w2 do
        if cacheBuf[i] and cacheBuf[i].idx == i then
            parts[#parts + 1] = cacheBuf[i].data
        else
            missing = missing + 1
        end
    end
    if missing == 0 then
        SL:ShowSystemTips("战报接收完成：" .. #table.concat(parts) .. " 字节")
        cacheBuf = {}
    end
end
SL:RegisterLuaNetMsg(10001, onChunk, nil)