【框架设计】宠物探险：离线探险时长与收益结算

---宠物探险：派遣与档位选择
local EXPEDITIONS = {
    { hours = 4,  reward = 40 },
    { hours = 8,  reward = 80 },
    { hours = 12, reward = 150 },
}

function Pet.explore(actor, tier)
    local player = class(actor)
    if not player then return false end
    local busy = getplayvar(actor, 2, "PetExploreEnd")
    if busy and busy ~= "" and tonumber(busy) > os.time() then
        sendmsg(actor, 1, "宠物仍在探险中")
        return false
    end
    local cfg = EXPEDITIONS[tier]
    local endAt = os.time() + cfg.hours * 3600
    setplayvar(actor, "HUMAN", "PetExploreEnd", endAt, 1)
    setplayvar(actor, "HUMAN", "PetExploreTier", tier, 1)
    sendmsg(actor, 1, "宠物已出发，" .. cfg.hours ..
        " 小时后带回收获")
    return true
end

---探险归来：按档位结算收获
function Pet.collect(actor)
    local endAt = tonumber(getplayvar(actor, 2, "PetExploreEnd")) or 0
    if os.time() < endAt then
        sendmsg(actor, 1, "宠物尚未归来，还剩 " ..
            math.ceil((endAt - os.time()) / 60) .. " 分钟")
        return false
    end
    local tier = tonumber(getplayvar(actor, 2, "PetExploreTier")) or 1
    local cfg = EXPEDITIONS[tier]
    giveitem(actor, "探险物资箱", 1)
    setplayvar(actor, "HUMAN", "PetExploreEnd", "", 1)
    sendmsg(actor, 1, "探险归来！获得物资箱 x" .. cfg.reward)
    return true
end