【Lua实战】时间轮算法：大量定时器的低开销管理

-- 时间轮：本体实现
local WHEEL = 60
local slots = {}
for i = 0, WHEEL - 1 do slots[i] = {} end
local cursor = 0
local function addTask(fn, delaySec)
    local slot = (cursor + delaySec) % WHEEL
    local t = slots[slot]
    t[#t + 1] = {fn = fn, round = math.floor(delaySec / WHEEL)}
end
local function tick()
    local cur = slots[cursor]
    local keep = {}
    for _, task in ipairs(cur) do
        if task.round > 0 then
            task.round = task.round - 1
            keep[#keep + 1] = task
        else
            task.fn()
        end
    end
    slots[cursor] = keep
    cursor = (cursor + 1) % WHEEL
end

-- 时间轮应用：Buff 到期管理
local player = class(actor)
local function addBuffTimed(player, buffName, seconds)
    addTask(function()
        local p = class(player)
        if p == nil then return end
        setplayvar(p, "HUMAN", "Buff_" .. buffName, 0, true)
        sendmsg(p, 1, 0, buffName .. " 效果已消失。")
    end, seconds)
    setplayvar(player, "HUMAN", "Buff_" .. buffName, 1, true)
end