Lua循环同构：拼接自串的旋转判定

local function isRotate(a, b)
    if #a ~= #b then return false end
    for i = 1, #a do               -- 逐个旋转再比对，n次构造
        if a == string.sub(b, i) .. string.sub(b, 1, i - 1) then
            return true
        end
    end
    return false
end

local function isRotate(a, b)
    return #a == #b and string.find(a .. a, b, 1, true) ~= nil
end
sendmsg(actor, 1, "循环同构："
    .. tostring(isRotate("金币宝箱", "宝箱金币")))