【框架设计】淬炼系统：淬炼次数与元素抗性的成长线

---淬炼：消耗淬炼石，抗性逐次成长
function Temper.run(actor, slot)
    local lv = tonumber(getplayvar(actor, 2, "Temper_" .. slot)) or 0
    if lv >= 5 then
        sendmsg(actor, 1, "淬炼已达上限")
        return false
    end
    local cost = 4 + lv
    if not checkitemw(actor, "淬炼石", cost) then
        sendmsg(actor, 1, "淬炼石不足，需要 " .. cost .. " 枚")
        return false
    end
    takeitem(actor, "淬炼石", cost, 0, "淬炼消耗")
    setplayvar(actor, "HUMAN", "Temper_" .. slot, lv + 1, 1)
    Temper.apply(actor, slot, lv + 1)
    return true
end

---抗性生效：BUFF 承载毒抗与火抗
function Temper.apply(actor, slot, lv)
    if slot == 1 then
        -- 武器位淬炼出攻击强化
        addbuff(actor, 21001, 99999, 1, actor, { [1] = lv * 8 })
    else
        -- 防具位淬炼出毒抗
        addbuff(actor, 21002, 99999, 1, actor, { [6] = lv * 3 })
    end
    if lv == 5 then
        sendmsg(nil, 1, actor:GetName() .. " 的装备淬炼圆满")
    end
end