Lua猴子分桃：逆推法的倒着求解

local function tryForward(start)
    local n = start
    for i = 1, 5 do
        if n % 5 ~= 1 then return false end
        n = n - 1 - math.floor((n - 1) / 5)
    end
    return n % 5 == 0
end

local function backward()
    local total = 5 ^ 5 - 4
    local n = total
    for i = 1, 5 do
        n = (n - 1) * 4 / 5
    end
    return total, n
end
local p = getplayerbyname("peach01")
local total, left = backward()
sendmsg(p, 1, "最少 " .. total .. " 个，末轮剩 " .. left)