【入门夯实】table.remove的返回值：删除即取值的一步写法

local queue = {"甲", "乙", "丙"}
local first = queue[1]
table.remove(queue, 1)
local second = queue[1]
table.remove(queue, 1)

local function sendTop3(actorName, queue)
    local actor = getplayerbyname(actorName)
    local prizes = { "裁决之杖", "骨玉权杖", "龙纹剑" }
    for i = 1, 3 do
        local winner = table.remove(queue, 1)
        if winner == actorName then
            sendmsg(actor, 1, "获得奖励：" .. prizes[i])
            giveitem(actor, prizes[i], 1, 1, "行会战前3奖励")
        end
    end
end

local stack = {}
table.insert(stack, "A")
table.insert(stack, "B")
local top = table.remove(stack)

for i = #queue, 1, -1 do
    if queue[i] == "黑名单玩家" then
        table.remove(queue, i)
    end
end