【Lua实战】协程超时：长时间任务的看门狗治理

-- 协程看门狗：启动与监控
local player = class(actor)
local TASK_TIMEOUT = 30
local runningTasks = {}
local function startTask(player, taskName, taskFn)
    local co = coroutine.create(taskFn)
    runningTasks[taskName] = {co = co, start = os.time()}
    local ok, err = coroutine.resume(co)
    if not ok then
        runningTasks[taskName] = nil
        sendmsg(player, 1, 0, taskName .. " 执行异常：" .. tostring(err))
    end
end
local function checkTimeouts(player)
    local now = os.time()
    for name, task in pairs(runningTasks) do
        if now - task.start > TASK_TIMEOUT then
            runningTasks[name] = nil
            sendmsg(player, 1, 0, "任务 " .. name .. " 超时终止。")
        end
    end
end

-- 批量发奖：看门狗保护
local player = class(actor)
local function batchReward(player, rewardList)
    local completed = {}
    for i, entry in ipairs(rewardList) do
        local mate = class(entry.name)
        if mate then
            giveitem(mate, entry.item, entry.count)
            completed[#completed + 1] = entry.name
        end
    end
    sendmsg(player, 1, 0, "批量发奖完成，共发放 " .. #completed .. " 人。")
end