【运维发布】应急预案分级：P0 到 P3 事件的响应矩阵

-- 应急预案：事件分级
local player = class(actor)
local LEVELS = {
    P0 = {respond = 300, notice = "全服公告", owner = "总监"},
    P1 = {respond = 900, notice = "值班+主管", owner = "主程"},
    P2 = {respond = 3600, notice = "值班", owner = "模块负责人"},
    P3 = {respond = 86400, notice = "工单", owner = "客服"},
}
local function classifyAndNotify(player, level, desc)
    local cfg = LEVELS[level]
    if cfg == nil then
        sendmsg(player, 1, 0, "未知事件等级，请先确认分级。")
        return
    end
    sendmsg(player, 1, 0, level .. " 级事件已登记：" .. desc ..
        "，响应时限 " .. cfg.respond / 60 .. " 分钟，责任线：" .. cfg.owner)
end

-- 响应矩阵：升级与收尾
local player = class(actor)
local NEXT = {P3 = "P2", P2 = "P1", P1 = "P0"}
local function escalate(player, level, reason)
    local up = NEXT[level]
    if up == nil then return end
    sendcentermsg(player, 255, 0, level .. " 级事件升级为 " .. up ..
        "：" .. reason, 0, 10)
    classifyAndNotify(player, up, reason)
end
local function closeIncident(player, level, desc)
    sendmsg(player, 1, 0, level .. " 级事件已恢复，进入收尾验证。")
    if level == "P0" or level == "P1" then
        setsysvarex("ReviewDue", os.date("%Y%m%d", os.time() + 172800), true)
        sendmsg(player, 1, 0, "复盘报告需在 48 小时内提交并全员公示。")
    end
end