【运维发布】降级开关：非核心功能的快速关闭

-- 降级开关：矩阵与状态
local player = class(actor)
local SWITCHES = {rank = 1, achievePush = 1, redDot = 1}
local function isDown(name)
    return SWITCHES[name] == 0
end
local function refreshRank(player)
    if isDown("rank") then
        sendmsg(player, 1, 0, "排行榜暂时维护中，数据可能延迟。")
        return
    end
    sendmsg(player, 1, 0, "排行榜数据已刷新。")
end

-- 快速切换：一键与单项
local player = class(actor)
local function setSwitch(player, name, state)
    if name == "all" then
        for k in pairs(SWITCHES) do
            SWITCHES[k] = state
        end
        sendmsg(player, 1, 0, "已" .. (state == 0 and "一键降级" or "一键恢复") .. "全部非核心功能。")
        return
    end
    if SWITCHES[name] == nil then
        sendmsg(player, 1, 0, "未知开关名。")
        return
    end
    SWITCHES[name] = state
    sendmsg(player, 1, 0, name .. " 开关已" .. (state == 0 and "关闭" or "开启") .. "。")
    setsysvarex("SwitchAudit", os.date("%H%M%S") .. "|" .. name .. "|" .. state, true)
end