local zhuanpanOBJ = {}
zhuanpanOBJ.Name = "zhuanpanOBJ"
zhuanpanOBJ.cfg = {
[1] = {
["id"] = 100004,
["reward"] = {
[1] = {
[1] = 321,
[2] = 5,
},
},
["showR
🤖 回答引擎: 前端Lua |
🕒 时间: 2026-03-09 16:06:50 |
👁️ 阅读: 10
我来帮你简化这个配置表。从你的代码来看,很多字段是重复的,可以进行合并优化:
```lua
local zhuanpanOBJ = {}
zhuanpanOBJ.Name = "zhuanpanOBJ"
zhuanpanOBJ.cfg = {
[1] = { id = 100004, reward = { {321, 5} }, showReward = { {19, 12} }, index2 = 1 },
[2] = { id = 100004, reward = { {4, 1000000} }, showReward = { {19, 18} }, index2 = 2 },
[3] = { id = 100004, reward = { {273, 2} }, showReward = { {19, 20} }, index2 = 3 },
[4] = { id = 100004, reward = { {297, 3} }, showReward = { {19, 30} }, index2 = 4 },
[5] = { id = 100004, reward = { {4, 5000000} }, showReward = { {19, 60} }, index2 = 5 },
[6] = { id = 100004, reward = { {308, 1} }, showReward = { {19, 70} }, index2 = 6 },
[7] = { id = 100004, reward = { {281, 200} }, showReward = { {19, 90} }, index2 = 7 },
[8] = { id = 100004, reward = { {280, 50} }, showReward = { {19, 233} }, index2 = 8 },
[9] = { id = 100004, reward = { {249, 3} }, showReward = { {19, 233} }, index2 = 9 },
}
```
**简化说明:**
1. 移除了多余的`[1] = `这种嵌套写法,直接使用`{ }`包含数组
2. 将`[1] = { [1] = 321, [2] = 5 }`简化为`{321, 5}`
3. 保持数据结构不变,只是写法更简洁
这样写代码更清晰,维护起来也更方便。如果需要进一步优化,可以考虑:
- 如果所有项的`id`都是100004,可以提到外层统一设置
- 使用循环生成部分重复数据
不过根据浮生梦老师前端课程内容,这样的简化已经足够清晰易读了。
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